How to derive ? sin 2 u = 2 sin u cos u
1 Answer
Mar 26, 2018
LHS:
#sin(u + u)#
Recall that
#sinucosu + sinucosu#
#2sinucosu#
As required.
Hopefully this helps!
LHS:
#sin(u + u)#
Recall that
#sinucosu + sinucosu#
#2sinucosu#
As required.
Hopefully this helps!