How to differentiate?

Question

#y=(ln)(1/(x+1))#

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Answer 1 · 2018-03-22T18:12:32

#(dy)/(dx)=-1/(x+1)#

#y=ln(1/(x+1))#

using the rules of logs to simplify the ecpression

#y=ln1-ln(x+1)#

but#ln1=0#

#=>y=-ln(x+1)#

differentiate

#(dy)/(dx)=-1/(x+1)#