How to differentiate 3/π sinx°?

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Answer 1 · 2018-04-03T18:29:29

#f^'(x)=1/60cos((pix)/180)#

Let,

#f(x)=3/pisinx^0#

Now, #color(red)(x^0=(x*pi/180)^R=(pix)/180#

So,

#f(x)=3/pi*sin((pix)/180)#

#"Using "color(blue)"Chain Rule"#

#:.f^'(x)=3/pi*cos((pix)/180)d/(dx)((pix)/180)#

#=3/picos((pix)/180)(pi/180)#

#=3/cancelpi*cancelpi/180cos((pix)/180)#

#=1/60cos((pix)/180)#