How to do you graph #y=4x-1# by plotting points?

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Answer 1 · 2018-03-04T14:28:14

See a solution process below:

To graph a linear equation you require just two points and then draw a straight line through the two points.

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = (4 * 0) - 1#

#y = 0 - 1#

#y = -1# or #(0, -1)#

Second Point: For #x = 1#

#y = (4 * 1) - 1#

#y = 4 - 1#

#y = 3# or #(1, 3)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+1)^2-0.025)((x-1)^2+(y-3)^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y-4x+1)(x^2+(y+1)^2-0.025)((x-1)^2+(y-3)^2-0.025)=0 [-10, 10, -5, 5]}