Question

How to factor 9x2=25 ?

Answer 1

Assuming you mean `9x^2=25`:
`(3x+5)(3x-5)`

Explanation:

Assuming you mean `9x^2=25`:

Before we factor, we want to set this equal to zero. We can do that by subtracting 25 from both sides of the equation to get:

`9x^2-25=0`

It is important to realize that this is a difference of squares , as both terms in this equation are perfect squares. This will be in the form `(ax+b)(ax-b)`, where `a` will be the square root of `9x^2` and b will be the square root of `25`.

The square root of `9x^2` is `3x` and the square root of `25` is `+-5`. Thus, we can factor this as:

`(3x+5)(3x-5)`

If the term "difference of squares" seems foreign to you, I encourage you to Google it or even look it up on Khan Academy and get some practice at it.