# How to find the asymptotes for #(3x^2) / (x^2-4)#?

##### 1 Answer

Aug 11, 2018

#### Answer:

#### Explanation:

Note that:

#lim_(x->+-oo) (3x^2)/(x^2-4) = lim_(x->+-oo) 3/(1-4/x^2) = 3#

So

Also:

#x^2-4 = (x-2)(x+2)#

So the denominator is zero when

So

graph{(y-(3x^2)/(x^2-4)) = 0 [-10.09, 9.91, -3.6, 6.4]}