How to find the equation of the tangent?
1 Answer
Mar 8, 2018
Explanation:
#•color(white)(x)m_(color(red)"tangent")=f'(1/k)#
#"differentiate using the "color(blue)"chain rule"#
#"given "f(x)=g(h(x))" then"#
#f'(x)=g'(h(x))xxh'(x)larrcolor(blue)"chain rule"#
#"here "f(x)=ln(kx)larr"log_e x=lnx#
#rArrf'(x)=1/(kx)xxd/dx(kx)=1/x#
#rArrf'(1/k)=1/(1/k)=k=m_("tangent")#
#"equation with "m=k" and "(1/k,0)#
#y=k(x-1/k)#
#rArry=kx-1larrcolor(red)"equation of tangent"#
