Question

How to graph a parabola `y=(1/8)x^2`?

Answer 1

Graph the parabola `y=1/8x^2` .

Determine points on the parabola. You must include positive and negative values for `x`.

If `x=-4; y=(1/8)(-4)^2=1/cancel8^1*cancel16^2=2`; Point `(-4, 2)`

If `x=-2; y=(1/8)(-2)^2=1/cancel8^2*cancel4^1=1/2`; Point `(-2, 1/2)`

If `x=0; y=1/8`; Point `(0,1/8)`

If `x=2; y=1/8(2)^2=1/cancel8^2*cancel4^1=1/2`; Point `(2,1/2)`

If `x=-4; y=1/8(-4)^2=1/cancel8^1*cancel16^2=2`; Point `(-4,2)`

Plot the points and connect the points.

graph{y=1/8x^2 [-6.25, 6.244, -3.13, 3.12]}