How to graph a parabola #y=(1/8)x^2#?

1 Answer
May 15, 2015

Graph the parabola #y=1/8x^2# .

Determine points on the parabola. You must include positive and negative values for #x#.

If #x=-4; y=(1/8)(-4)^2=1/cancel8^1*cancel16^2=2#; Point #(-4, 2)#

If #x=-2; y=(1/8)(-2)^2=1/cancel8^2*cancel4^1=1/2#; Point #(-2, 1/2)#

If #x=0; y=1/8#; Point #(0,1/8)#

If #x=2; y=1/8(2)^2=1/cancel8^2*cancel4^1=1/2#; Point #(2,1/2)#

If #x=-4; y=1/8(-4)^2=1/cancel8^1*cancel16^2=2#; Point #(-4,2)#

Plot the points and connect the points.

graph{y=1/8x^2 [-6.25, 6.244, -3.13, 3.12]}