How to graph a parabola y>x^2+2x-3?

The function can be rewritten as $y > \left(x - 1\right) \left(x + 3\right)$
This gives you the Zeroes $x = 1 \mathmr{and} x = - 3$
The minimum will be reached halfway between those (when $x = - 1$) at the point $\left(- 1 , - 4\right)$