How to plot the graph of #y = - cos (2x - pi) + 1#?

1 Answer
Apr 1, 2018

Answer:

As below.

Explanation:

#y = A cos (Bx - C) + D#

Given #y = - cos (2x -pi) + 1#

#Amplitude = |A| = |-1| = 1#

#"Period " = (2pi) / |B| = (2pi) / 2 = pi#

#"Vertical Shift " = D = 1#

#"Phase Shift " = C / B = pi / 2, " " pi/2 " to the right"#

graph{- cos(2x - pi) + 1 [-10, 10, -5, 5]}