How to put this polar equation in rectangular format? r=(1)/(-8cos theta-3sin theta)

1 Answer
Feb 1, 2018

# 8x+3y +1 = 0 \ \ #, a straight line

Explanation:

We have a polar equation:

# r=(1)/(-8cos theta-3sin theta) #

Then using:

# x=rcostheta# and #y=rsintheta#

We can write the equation as:

# r=(-r)/(8x+3y) #
# :. 1 =(-1)/(8x+3y) #
# :. 8x+3y =-1 #
# :. 8x+3y +1 = 0 \ \ #, a straight line