How to put this polar equation in rectangular format? r=(1)/(-8cos theta-3sin theta)
1 Answer
Feb 1, 2018
# 8x+3y +1 = 0 \ \ # , a straight line
Explanation:
We have a polar equation:
# r=(1)/(-8cos theta-3sin theta) #
Then using:
# x=rcostheta# and#y=rsintheta#
We can write the equation as:
# r=(-r)/(8x+3y) #
# :. 1 =(-1)/(8x+3y) #
# :. 8x+3y =-1 #
# :. 8x+3y +1 = 0 \ \ # , a straight line