How to reach this result " #5pi/6# with : 2arcsin(1)-1arcsin(1/2)= What are the steps?

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Answer 1 · 2018-03-18T18:10:45

#(5pi)/6#

#2arcsin(1)-1arcsin(1/2)#

Looking at the unit circle, at what angle is sin (y-coordinate) equal to 1, remembering arcsin is only defined in quadrant 1 and 4:

Looking at the unit at what angle is sin (y-coordinate) equal to 1/2, remembering arcsin is only defined in quadrant 1 and 4:

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Substitute in angle values for the inverse trig:

#2(pi/2)-1(pi/6)#

#pi-pi/6#

#(6pi)/6-pi/6#

#(5pi)/6#