# How to solve 2cos^(2)x-sinx=1 ?

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I do understand how I get sinx which is sinx=1/2 and sinx=-1 but I do not understand what I should do next. I know that I should look at the unit circle and when I do that I get 3pi/2, pi/6 and 5pi/6 but the answer is x=pi/6+n2pi/3

I do understand how I get sinx which is sinx=1/2 and sinx=-1 but I do not understand what I should do next. I know that I should look at the unit circle and when I do that I get 3pi/2, pi/6 and 5pi/6 but the answer is x=pi/6+n2pi/3

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Oct 24, 2017

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