How to solve 64^-4/3?
1 Answer
May 9, 2018
Explanation:
#"using the "color(blue)"laws of exponents"#
#•color(white)(x)a^-mhArr1/a^m#
#•color(white)(x)a^(m/n)hArr(root(n) a))^m#
#rArr64^(-4/3)=1/64^(4/3)=1/256#
#64^(4/3)=(root(3) 64)^4=(4)^4=256#