How to solve #(8/27)^(-4/3)#?

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Answer 1 · 2018-05-12T14:40:05

#color(magenta)(=>(81/16)#

#(8/27)^(-4/3)#

Since #8=2^3 and 27=3^3#

#=>(2^3/3^3)^(-4/3)#

Using the law: #color(blue)((a/b)^m=a^m/b^m#

#=>2^[3xx(-4)/ 3]/3^[3xx(-4)/3]#

#=>2^(-4)/3^(-4)#

Using the law: #color(blue)(a^-m=1/a^m and 1/a^-m=a^m#

#=>3^4/2^4#

#color(magenta)(=>81/16#

~Hope this helps! :)