If a point P has coordinates (0,-2) and Q is any point on the circle, x^2+y^2 -5x-y+5=0, then what is the maximum value of (PQ)^2?
1 Answer
Mar 18, 2018
Answer is (2).
Explanation:
The center of the circle
Let us put the values of the corrdinates of
distance of
Distance of
and hence the maximum value of
=
=
Hence answer is (2).
graph{(x^2+(y+2)^2-0.01)(x^2+y^2-5x-y+5)=0 [-3.917, 6.083, -2.48, 2.52]}