How to write standard form of the equation circle with a center of (-1,4);circumference 6pie?
1 Answer
Mar 19, 2018
Explanation:
#"the equation of a circle in standard form is"#
#color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|)))#
#"where "(a,b)" are the coordinates of the centre and r is"#
#"the radius"#
#"we have the centre but require to find r"#
#"circumference "=2pir=6pi#
#rArrr=(6pi)/(2pi)=3#
#rArr(x+1)^2+(y-4)^2=9larrcolor(red)"equation of circle"#