How to you find the general solution of dy/dx=3x^3?

Nov 14, 2016

$y = \frac{3}{4} {x}^{4} + C$

Explanation:

$\mathrm{dy} = 3 {x}^{3} \mathrm{dx}$

$\int \left(\mathrm{dy}\right) = \int \left(3 {x}^{3} \mathrm{dx}\right)$

By the power rule, $\int \left({x}^{n}\right) \mathrm{dx} = {x}^{n + 1} / \left(n + 1\right)$

$y = \frac{3}{4} {x}^{4} + C$

Hopefully this helps!