How would I Solve for b if #b/(4+isqrt3) - b/(4-isqrt3) =1# ?

1 Answer
Feb 12, 2018

#b=19/(2sqrt3)i#

Explanation:

#b/(4+isqrt3)-b/(4-isqrt3)=1#

means #(b(4-isqrt3)-b(4+isqrt3))/((4-isqrt3)(4+isqrt3))=1#

or #(-2sqrt3bi)/(4^2+(sqrt3)^2)=1#

or #(-2sqrt3bi)/19=1#

or #b=-19/(2sqrt3i)=-19/(2sqrt3)xx(-i)=19/(2sqrt3)i#