# How would you balance C8 H18 + O2 = CO2 +H20?

Oct 19, 2015

You have octane. Under complete combustion there MUST be 8 equivalents carbon dioxide as a consequence. Water is the other product; how many equiv water result? And how many equiv oxygen gas are used?

#### Explanation:

If I were to combust heptane, I would formulate the combustion rxn this way:

${C}_{7} {H}_{16} + 11 {O}_{2} \rightarrow 7 C {O}_{2} + 8 {H}_{2} O$

You have octane. How are you going to modify the equation?