# How would you balance the following equation: NH3 + H2SO4 --> (NH4)2SO4?

Dec 21, 2015

Multiply the $N {H}_{3}$ by $2$.

#### Explanation:

To balance the below reaction you will need to multiply the $N {H}_{3}$ by $2$.

$\textcolor{red}{2} N {H}_{3} + {H}_{2} S {O}_{4} \to {\left(N {H}_{4}\right)}_{2} S {O}_{4}$

Then you will have:

$2 N$ to the left and $2 N$ to the right.

$8 H = \left(2 \times \textcolor{b l u e}{3}\right) \text{ from " 2NH_(color(blue)(3)) +color(red)(2)" from } {H}_{\textcolor{red}{2}} S {O}_{4}$ to the left and $8 H = 2 \times \textcolor{g r e e n}{4} \text{ from } {\left(N {H}_{\textcolor{g r e e n}{4}}\right)}_{2} S {O}_{4}$ to the right.

$S {O}_{4}$ to the left and $S {O}_{4}$ to the right.