# How would you calculate the maximum number of grams of CaCl2 that could be produced from 74g of Ca(OH)2 in the following reaction: 2HCl + Ca(OH)2 --> 2H2O + CaCl2?

Dec 9, 2015

#### Answer:

$111 g$

#### Explanation:

First calculate the number of moles of calcium hydroxide in the 74 grams :
$n = \frac{m}{{M}_{r}} = \frac{74}{40 + 32 + 2} = 1 m o l$

Therefore, providing sufficient hydrochloric acid is added, the maximum amount of calcium calcium chloride that can be formed is also 1 mole (in order to satisfy the mole ratio in the balanced chemical reaction).

But 1 mole of calcium chloride corresponds to a mass of

$m = n \times {M}_{r} = 1 \times \left(40 + 2 \times 35 , 5\right) = 111 g$