Question

How would you calculate the molarity of the following solution: 0.900 mol of `Na_2S` in 1.10 L of solution?

Answer 1

`"Molarity"` `=` `"Moles of sodium sulfide"/"Volume of solution"`

Explanation:

`=` `(0.900*mol)/(1.10*L)` `=` `0.818*mol*L^-1` with respect to `"sodium sulfide"`. What is the concentration with respect to `Na^+(aq)` ion?