# How would you find P and A of the equation f(x)=PA^x given f(2)=5400 and f(6)= 345000?

A=(575/27)^(1/3 and $P = 5400 {\left(\frac{27}{575}\right)}^{\frac{2}{3}}$, nearly
$f \left(6\right) = P {A}^{6} = 345000 \mathmr{and} f \left(2\right) = P {A}^{2} = 5400.$
Upon division, ${A}^{3} = \frac{575}{27.}$ So, #A=(57527)^(1/3)y.
$P = \frac{5400}{A} ^ 2 = 5400 {\left(\frac{27}{575}\right)}^{\frac{2}{3}}$..