How would you graph the line #2x+8=0#? Algebra Graphs of Linear Equations and Functions Graphs Using Slope-Intercept Form 1 Answer iceman Jul 31, 2016 A vertical line at #x=-4# Explanation: #2x+8=0# => solving for x: subtract 8 from both sides: #2x=-8# => divide both sides by 2: #x=-4# => this is the equation of a vertical line at #x=-4# Answer link Related questions How do you graph #2x-3y=6# using slope intercept form? How do you graph a line using slope-intercept form? Does a graph always have a y-intercept? Where is the y-intercept of #y=2x+0.5# on a graph? How do you graph #y=-3x+5# using slope intercept form? Once you graph the y-intercept, how do you determine the second point? How do you know if you graphed the linear equation correctly? How do you graph #y=-\frac{1}{5}x-11#? How do you graph #2x + 5y = 10# using the slope and y-intercept? How do you graph #3x-5y= 10# using the slope and y intercept? See all questions in Graphs Using Slope-Intercept Form Impact of this question 4486 views around the world You can reuse this answer Creative Commons License