# How would you multiply (x+8)(x - 8)?

${x}^{2} - 64$
$\left({a}^{2} - {b}^{2}\right) = \left(a + b\right) \left(a - b\right)$
If we let $a = x$ and $b = 8$
$\left({x}^{2} - {8}^{2}\right) = \left(x + 8\right) \left(x - 8\right)$