How would you simplify #sqrt2 times 5 sqrt2#?

2 Answers
Apr 21, 2018

Answer:

#10#

Explanation:

Multiplying radicals is similar to regular multiplying. You will multiply the terms outside the square roots together and multiply the terms inside the square root together.

#sqrt2 xx 5sqrt2#

Let's change it a little to give the first quantity a number outside the square root:

#1sqrt2 xx 5sqrt2#

Anything multiplied by #1# is itself, so it doesn't change the value of the expression for it to be there.

Now multiply the outside numbers and inside numbers together:

#1 xx 5sqrt(2xx2)#

#5sqrt4#

#5(2) rarr 10#

Apr 22, 2018

Answer:

#10#

Explanation:

Given: #sqrt2*5sqrt2#

Rearrange into:

#=>sqrt2*sqrt2*5#

#=(sqrt2)^2*5#

#=2*5#

#=10#