How would you write each expression in terms of sin θ and cos θ and simplify?

#tan^2 θ (1 + cot^2 θ)#

1 Answer
Apr 1, 2018

#1/cos^2theta#

Explanation:

Recall that

#tantheta=sintheta/costheta#

#tan^2theta=sin^2theta/cos^2theta#

Furthermore, recall the Pythagorean identity

#1+cot^2theta=csc^2theta#

And that #csc^2theta=1/sin^2theta#

So, we have

#cancel(sin^2theta)/cos^2theta*1/cancel(sin^2theta)#

Leaving us with

#1/cos^2theta# if we're staying in terms of sine and cosine.