How would you write the formula of the conjugate base of the Bronstead-Lowry acids H2SO3 and HI?

1 Answer
Jul 17, 2018

Answer:

for #H_2SO_3#: the conjugate base is #HSO_3^-#

for #HI#: the conjugate base is #I^-#

Explanation:

Given: Bronstead-Lowry acids #H_2SO_3# and #HI#

Bronstead-Lowry acid, base equation:

#B + HA iff HB^+ + A^-#

where #B#: base proton receiver; #" "HA# is the acid proton donor;

#HB^+# is the conjugate acid; #" "A^-# is the conjugate base

For sulfurous acid # (H_2SO_3)#:

#H_2SO_3 (aq) + H_2O (l) iff H_3O^+ (aq) + HSO_3^- (aq)#

the conjugate base is #HSO_3^-#

For hydroiodic acid #(HI)#:

#HI (aq) + H_2O (l) iff H_3O^+ (aq) + I^- (aq)#

the conjugate base is #I^-#