How you test 69,902 for divisibility by 2, 3, 5, 9, or 10?

1 Answer
Mar 10, 2018

#69902# is divisible only by #2# and not by #3,5,9# or #10#. Please see below for details.

Explanation:

Divisibility by #2# can be tested by checking the digit at unit's place. If we have #0,2,4,6# or #8# at unit's place, then the number is divisible by #2#. Here we have #2# at unit's place in #69902#, and hence it is divisible by #2#.

Divisibility by #3# can be tested by checking that sum of all the digits is divisible by #3# or not. Here sum of digit's in #69902# is #6+9+9+0+2=26#, which is not divisible by #3#, therefore #69902# is not divisible by #3#.

Divisibility by #5# can be tested by checking the digit at unit's place. If we have #0# or #5# at unit's place, then the number is divisible by #5#. Here we have #2# at unit's place in #69902#, and hence it is not divisible by #5#.

Divisibility by #9# can be tested by checking that sum of all the digits is divisible by #9# or not. Here sum of digit's in #69902# is #6+9+9+0+2=26#, which is not divisible by #9#, therefore #69902# is not divisible by #9#. Note that if a number is not divisible by #3#, it is also not divisible by #9#.

Divisibility by #10# can be tested by checking the digit at unit's place. If we have #0# at unit's place, then the number is divisible by #10#. Here we have #2# at unit's place in #69902#, and hence it is not divisible by #10#.