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Answer 1 · 2018-04-03T09:18:51

Answer A

#(a^2b^(-1))/sqrt(ab^3)=(a^2b^(-1))/(a^(1/2)b^(3/2))=a^(2-1/2)b^(-1-3/2)=a^(3/2)b^(-5/2)=a^(3/2)/b^(5/2)#

Answer 2 · 2018-04-03T10:43:56

#a^(3/2)/b^(5/2)#
Hence A

#(a^2color(red)(b^-1))/color(blue)(sqrt(ab^3)" "larr sqrtx = x^(1/2)#

#= a^2 /(color(blue)(a^(1/2) b^(3/2)) color(red)(b^1))" "larr b^-1 = 1/b#

#=(a^(2-1/2))/(b^(3/2+2/2)) #

#=a^(3/2)/b^(5/2)#