I don't know how to find the restrictions on #"5(4x-2)"/" 8(2x-1)^2 "#?

It's a power of 2 to that whole bracket.

1 Answer
Jim G.
Feb 22, 2018

#x!=1/2#

Explanation:

#"the restrictions on a rational function are any values of x"#
#"that make the function undefined "#

#"the denominator of the rational function cannot be zero"#
#"as this would make it undefined"#

#"Equating the denominator to zero and solving gives the"#
#"values that x cannot be"#

#"solve "8(2x-1)^2=0#

#rArr2x-1=0rArrx=1/2larrcolor(red)"excluded value"#

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