I drop a 60 g golfball from 2 m high. It rebounds to 1.5 m. How much energy is lost? c

1 Answer
Junaid Mirza
Apr 8, 2018

#"0.294 Joule"#

Explanation:

Total energy before when to ball is dropped is

#"T.E"_i = "mgh" = "0.06 kg × 9.8 m/s"^2 × "2 m" = "1.176 Joule"#

Total energy after when it rebounds is

#"T.E"_f = "mgh" = "0.06 kg × 9.8 m/s"^2 × "1.5 m" = "0.882 Joule"#

Energy lost is

#Δ"T.E" = "T.E"_i - "T.E"_f = "1.176 J - 0.882 J = 0.294 J"#

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