I have some chair and tables.If i place two chair at each table ,I have extra chair.If i place 3 chairs at each table,i have one table with no chairs.What is the sum of the total umber of tables and chairs?

IQ question ,please ans anyhow and fast

Nov 15, 2016

$4$ tables and $9$ chairs

Explanation:

Let $t$ be the number of tables
and $c$ be the number of chairs.

If I place two chairs at each table, I have extra chair.
$\rightarrow c = 2 t + 1$

If I place 3 chairs at each table, I have one table with no chairs.
$\rightarrow c = 3 \left(t - 1\right)$

Therefore
$\textcolor{w h i t e}{\text{XXX}} 2 t + 1 = 3 \left(t - 1\right)$

$\textcolor{w h i t e}{\text{XXX}} 2 t + 1 = 3 t - 3$

$\textcolor{w h i t e}{\text{XXX}} 4 = t$

and since $c = 2 t + 1$
$\textcolor{w h i t e}{\text{XXX}} c = 2 \times 4 + 1 = 9$

Nov 15, 2016

4 tables 9 chairs

Explanation:

Let the count of chairs be $c$
Let the count of tables be $t$

Breaking down the question into its component parts:

$\textcolor{b r o w n}{\text{If I have two chairs at each table I have an extra chair}}$

$c = 2 t + 1$

$\textcolor{b r o w n}{\text{If I have one table to three chairs I have 1 table with no chairs}}$

$c = 3 \left(t - 1\right)$

$\implies 2 t + 1 = c = 3 \left(t - 1\right)$

$2 t + 1 = 3 t - 3$

$3 t - 2 t = 1 + 3$

$t = 4$

But $c = 2 t + 1$

$\implies c = 2 \left(4\right) + 1 = 9$