# I've got a car with an internal volume of 12000 L. If I drive my car into the river and it implodes, what will be the volume of the gas when the pressure goes from 1.0 atm to 1.4 atm?

May 21, 2017

We use Boyle's Law: ${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

Rearanging: ${V}_{2} = \frac{{P}_{1} {V}_{1}}{P} _ 2 = \frac{1.0 \times 12000}{1.4} = 8571$ $L$

#### Explanation:

The answer is all above, but let me share a tip. It's possible to memorise Boyle's, Charles' and Gay-Lussac's laws and use them appropriately.

But I find it simpler to just memorise the Combined Gas Law, and then leave out anything that does not change in a particular question:

$\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$

In this case, since temperature isn't mentioned, we simply leave it out and get Boyle's law.