(a) The chemical equation
The chemical equation is
#"2HI" ⇌ "H"_2 + "I"_2#
(b) The ICE table
#color(white)(mmmmmmml)"2HI" ⇌ "H"_ 2 + "I"_2#
#"I/mol·L"^"-1": color(white)(mm)2.00 color(white)(mm)0color(white)(mm)0#
#"C/mol·L"^"-1":color(white)(mm)"-2x" color(white)(mll)"+"xcolor(white)(m)"+"x#
#"E/mol·L"^"-1": color(white)(m)"2.00 -"2xcolor(white)(m)xcolor(white)(mll)x#
(c) The value of #x#
#["HI"] = 1.88 color(red)(cancel(color(black)("mol/L"))) = (2.00 - 2x) color(red)(cancel(color(black)("mol/L")))#
#2x = 2.00 - 1.88 = 0.12#
#x = 0.12/2 = 0.060#
(d) The value of #K_text(c)#
#K_text(c) = (["H"_2]["I"_2])/(["HI"]^2) = (0.060 × 0.060)/1.88^2 = 1.02 × 10^"-3"#
