# If 0.31 mol of Na_2SO_4 dissolve in water to make 740 mL of solution, how would you find the molarity of the resulting solution?

Mar 4, 2017

#### Answer:

$\text{Molarity"="Moles of solute"/"Volume of solution}$

#### Explanation:

And thus for the molarity of the given solution, we have:

$\frac{0.31 \cdot m o l}{740 \cdot \cancel{m L} \times {10}^{-} 3 \cdot L \cdot \cancel{m {L}^{-} 1}} = 0.42 \cdot m o l \cdot {L}^{-} 1$

with respect to $N {a}_{2} S {O}_{4}$. What is the molarity with respect to sodium ion?