Question

If `/_1` is a complement of `/_2` and `m/_2=36°`, what is `m/_1`?

Answer 1

`m/_1=54^o`

Explanation:

Complementary angles add up to `90^o`. As `/_1` is a complement of `/_2`

`m/_1+m/_2=90^o`

But `m/_2=36^o`

Hence `m/_1+36^o=90^o` and

`m/_1=90^o-36^o=54^o`