If (1/x + x) = 8, What will be the value of (x^3 + 1/x^3)?

if$\left(\frac{1}{x} + x\right) = 8$ find $\left({x}^{3} + \frac{1}{x} ^ 3\right)$

$\rightarrow x + \frac{1}{x} = 8$
$\rightarrow {x}^{3} + {\left(\frac{1}{x}\right)}^{3}$
$= {\left(x + \frac{1}{x}\right)}^{3} - 3 \cdot x \cdot \left(\frac{1}{x}\right) \cdot \left(x + \frac{1}{x}\right)$
$= {8}^{3} - 3 \cdot 8 = 488$