Question

If `12 L` of a gas at room temperature exerts a pressure of `9 kPa` on its container, what pressure will the gas exert if the container's volume changes to `4 L`?

Answer 1

`P_2=27" " kPa`

Explanation:

`"use Boyle's law"`
`P-1*V_1=P_2*V_2`
`9*cancel(12)=P_2*cancel(4)`
`P_2=9*3`
`P_2=27" " kPa`