If #18 L# of a gas at room temperature exerts a pressure of #15 kPa# on its container, what pressure will the gas exert if the container's volume changes to #5 L#?

1 Answer
Sep 29, 2016

Answer:

#54kPa#

Explanation:

Let's identify the known and unknown variables:

#color(orange)("Knowns:")#
- Initial Volume
- Final Volume
- Initial Pressure

#color(gray)("Unknowns:")#
- Final Pressure

We can obtain the answer using Boyle's Law quizlet.com

The numbers 1 and 2 represent the initial and final conditions, respectively.

All we have to do is rearrange the equation to solve for the final pressure.

We do this by dividing both sides by #V_2# in order to get #P_2# by itself like this:
#P_2=(P_1xxV_1)/V_2#

Now all we do is plug in the values and we're done!

#P_2= (15kPa xx 18cancel"L")/(5\cancel"L")# = #54kPa#