If 2.0 mL of 6.0M HCl is used to make a 500.0-mL aqueous solution, what is the molarity?

1 Answer
anor277
May 16, 2017

#"Molarity"="Moles of solute"/"Volume of solution"=0.024*mol*L^-1#

Explanation:

And thus..........#(6.0*mol*L^-1xx2.0xx10^-3*L)/(0.500*L)#

#=0.024*mol*L^-1#.

What is #pH# of this solution?

I forgot to remind you that the order of addition is important. While it is not crucial here, you ALWAYS add ACID to water, and never the reverse! Why? See here..........

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