Question

If 20 liter of gasoline costs 610 cent, how much would 35 liter cost?

Answer 1

See a solution process below

Explanation:

We can let the cost of `35` liters of gasoline equal: `c`

We can write:

`610"cents" = 20"liter"`

We can also write:

`c = 35"liter"`

If we divide the second equation by the first and solve for `c` we get:

`c/(610"cents") = (35"liter")/(20"liter")`

`c/(610"cents") = (35color(red)(cancel(color(black)("liter"))))/(20color(red)(cancel(color(black)("liter"))))`

`c/(610"cents") = 35/20`

`c/(610"cents") = (5 xx 7)/(5 xx 4)`

`c/(610"cents") = (color(red)(cancel(color(black)(5))) xx 7)/(color(red)(cancel(color(black)(5))) xx 4)`

`c/(610"cents") = 7/4`

`color(red)(610"cents") xx c/(610"cents") = color(red)(610"cents") xx 7/4`

`c = (4270"cents")/4`

`c = 1067.5"cents"`

Or

`1068` cents rounded to the nearest cent.