If 213 J raises a sample of water 8.2°C, what is the mass of the water?

1 Answer
Jul 2, 2017

Answer:

6.2 g

Explanation:

Use the formula #q=mCΔT#

q = heat absorbed or released, in joules (J)
m = mass
C = specific heat capacity (for water, it is #4.18 J / (g * K)#)
ΔT = change in temperature

Plug known values into the formula.

#213 = m(4.18)(8.2)#
#213 = 34.276m#
#6.214260707 = m#

The answer, expressed in 2 significant figures, is 6.2 g.

Hope this helps!