If 213 J raises a sample of water 8.2°C, what is the mass of the water?

Jul 2, 2017

6.2 g

Explanation:

Use the formula q=mCΔT

q = heat absorbed or released, in joules (J)
m = mass
C = specific heat capacity (for water, it is $4.18 \frac{J}{g \cdot K}$)
ΔT = change in temperature

Plug known values into the formula.

$213 = m \left(4.18\right) \left(8.2\right)$
$213 = 34.276 m$
$6.214260707 = m$

The answer, expressed in 2 significant figures, is 6.2 g.

Hope this helps!