Question

If 213 J raises a sample of water 8.2°C, what is the mass of the water?

Answer 1

6.2 g

Explanation:

Use the formula `q=mCΔT`

q = heat absorbed or released, in joules (J)
m = mass
C = specific heat capacity (for water, it is `4.18 J / (g * K)`)
ΔT = change in temperature

Plug known values into the formula.

`213 = m(4.18)(8.2)`
`213 = 34.276m`
`6.214260707 = m`

The answer, expressed in 2 significant figures, is 6.2 g.

Hope this helps!