If 3.38 g of #CuNO_3# is dissolved in water to make a 0.450 M solution, what is the volume of the solution?

1 Answer
anor277
Feb 6, 2017

I will assume you mean #"cupric nitrate"#, #Cu(NO_3)_2#.

Explanation:

#"Concentration"="Moles of solute"/"Volume of solution"#

And thus #"Volume of solution"="Moles of solute"/"Concentration"#

#=(3.38*g)/(187.56*g*mol^-1)xx1/(0.450*mol*L^-1)=0.040*L#

Are you happy with this treatment? All I have done is manipulated the quotient, to give me an answer in terms of #"volume"#.

Note that if they really asked for #"cuprous nitrate"#, #CuNO_3#, they should have known better. I doubt that you could isolate #"cuprous nitrate"#.

Related questions
See all questions in Molarity
Impact of this question
64734 views around the world
You can reuse this answer
Creative Commons License