# If 6.5 grams of CO react, how many liters of CO_2 are produce?

Jun 6, 2017

You need to specify standard conditions of temperature and pressure, for instance, $1 \cdot a t m$, and $298 \cdot K$.....and get approx. $160 \cdot L$

#### Explanation:

Now carbon monoxide oxidizes to give the same molar quantity of $C {O}_{2}$:

$C O \left(g\right) + \frac{1}{2} {O}_{2} \left(g\right) \rightarrow C {O}_{2} \left(g\right)$

Given the Ideal Gas Equation........

$V = \frac{n R T}{P} = \frac{\frac{6.5 \cdot g}{28.01 \cdot g \cdot m o {l}^{-} 1} \times 0.0821 \cdot \frac{L \cdot a t m}{K \cdot m o l} \times 298 \cdot K}{1 \cdot a t m}$

$\cong 160 \cdot L$.

Pressure is a state function of temperature, amount of gas, and volume, so we must make these extra assumptions to answer the question.