If 6.5 grams of CO react, how many liters of #CO_2# are produce?

1 Answer
Jun 6, 2017

Answer:

You need to specify standard conditions of temperature and pressure, for instance, #1*atm#, and #298*K#.....and get approx. #160*L#

Explanation:

Now carbon monoxide oxidizes to give the same molar quantity of #CO_2#:

#CO(g) + 1/2O_2(g) rarr CO_2(g)#

Given the Ideal Gas Equation........

#V=(nRT)/P=((6.5*g)/(28.01*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx298*K)/(1*atm)#

#~=160*L#.

Pressure is a state function of temperature, amount of gas, and volume, so we must make these extra assumptions to answer the question.