# If 69.5 kJ of heat is applied to a 1012-g block of metal, the temperature of the metal increases by 11.4°C. What is the specific heat capacity of the metal in J/g°C?

Feb 23, 2016

$= 6.024 J / g {.}^{\circ} C$

#### Explanation:

$W = m c \Delta T$

$\therefore c = \frac{W}{m \Delta T}$

=(69500J)/((1012g)(11.4^@C)

$= 6.024 J / g {.}^{\circ} C$.

(Note that the SI unit of specific heat capacity is actually $J / k g . K$).