# If 7/5 L of a gas at room temperature exerts a pressure of 30 kPa on its container, what pressure will the gas exert if the container's volume changes to 13/12 L?

Mar 5, 2018

The new pressure is $= 38.77 k P a$

#### Explanation:

Apply Boyle's Law

$\text{Pressure" xx "Volume" = "Constant}$ at, "Constant Tempertature"

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

The initial pressure is ${P}_{1} = 30 k P a$

The initial volume is ${V}_{1} = \frac{7}{5} L$

The final volume is ${V}_{2} = \frac{13}{12} L$

The final pressure is

${P}_{2} = {V}_{1} / {V}_{2} \cdot {P}_{1} = \frac{\frac{7}{5}}{\frac{13}{12}} \cdot 30 = 38.77 k P a$