Question

If 77 W of power is produced in 14 seconds, how much work is done?

Answer 1

Recall,

`bar P = W/t`

Hence,

`=> bar P t = W`

`therefore bar P t approx 1.08*10^3"J" = 1.08"kJ"`

of work is done in that time period, given that much power is used.

Answer 2

I got `1078 \ "J"~~1.08 \ "kJ"`.

Explanation:

Power is expressed in the equation,

`P=W/t`

where `W` is the work done in joules, and `t` is the time in seconds.

We need to solve for work, so we can rearrange the equation into

`W=P*t`

Plugging in the values, we get

`W=77 \ "W"*14 \ "s"=1078 \ "J"`

Then, we can convert to kilojoules if needed, which gives us approximately `1.08 \ "kJ"`. (since `1 \ "kJ"=1000 \ "J"`)