# If 8/3 L of a gas at room temperature exerts a pressure of 30 kPa on its container, what pressure will the gas exert if the container's volume changes to 7/4 L?

Apr 16, 2016

The final pressure is $45.7$ $k P a$.

#### Explanation:

The combined gas law is:

$\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$

In this case, the temperature doesn't change, so it can be removed:

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

Rearranging:

${P}_{2} = \frac{{P}_{1} {V}_{1}}{V} _ 2 = \frac{30 \cdot \left(\frac{8}{3}\right)}{\frac{7}{4}} = 45.7$ $k P a$